What is the hourly growth factor of a bacterium that undergoes cell division every 19 minutes?

Answer 1

Since the population doubles every 19 minutes, the rate of growth is 2^(t/19) where t is in minutes. (Assuming none die.)

To get the growth rate per hour, just adjust t so it is hours:

h = t/60, so t = 60h

2^(60h/19)