The formula to calculate the [H+] of a solution from its pH is:
[H+] = 10^(-pH)
Given that the pH of the solution is 7.9, we can plug in this value into the formula:
[H+] = 10^(-7.9)
Calculating this value gives:
[H+] ≈ 1.26 x 10^(-8) mol/L
Therefore, the [H+] of a solution with a pH of 7.9 is approximately 1.26 x 10^(-8) mol/L.
What is the [h+] of a solution with a ph of 7.9?
1 answer