what is the greatest mass that can be taken an exact number of times from 720kg,1008kg and 672kg?

Answer 1

720 = 2^4 * 3^2 * 5
1080 = 2^3 * 3^3 * 5
672 = 2^5 * 3 * 7

So, the largest number that evenly divides all of those is

2^3 * 3 = 24

Answer 2

let me rephrase the question ...

what is the greatest common factor of
720, 1008, and 672 ?

720 = 8*9*10 = 16*3*3*5
1008 = 8*9*14 = 16*3*3*7
672 = 16*3*2*7

so who is common?
looks like 16*3 or 48

check:
720/48 = 15
1008/48 = 21
672/48 = 14 , nothing common in any of those 3 answers.

Answer 3

I misread 1008 as 1080.
Go with Reiny.

Answer 4

2*2*2*2*3
48

Answer 5

720 1008 672
2 360 504 336
2 180 252 168
2 90 126 84
2 45 63 42
3 15 21 14

2*2*2*2*3=2^4*3 =48kg

Answer 6

24