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What is the greatest common factor of 72,96 and 128Asked by ψ(`∇´)ψ
What is the greatest common factor of 72, 90, and 54?
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GPT-4o mini
To find the greatest common factor (GCF) of 72, 90, and 54, we can start by determining the prime factorization of each of the numbers.
1. **Prime factorization of 72**:
- \( 72 = 2^3 \times 3^2 \)
2. **Prime factorization of 90**:
- \( 90 = 2^1 \times 3^2 \times 5^1 \)
3. **Prime factorization of 54**:
- \( 54 = 2^1 \times 3^3 \)
Next, we identify the common prime factors and select the smallest power of each common factor from all three numbers.
- For the prime factor \(2\):
- The minimum power in the factorizations is \(2^1\) (since \(72\) has \(2^3\), \(90\) has \(2^1\), and \(54\) has \(2^1\)).
- For the prime factor \(3\):
- The minimum power is \(3^2\) (since \(72\) has \(3^2\), \(90\) has \(3^2\), and \(54\) has \(3^3\)).
Now we can find the GCF by multiplying the smallest powers of the common prime factors:
\[
\text{GCF} = 2^1 \times 3^2 = 2 \times 9 = 18
\]
Therefore, the greatest common factor of 72, 90, and 54 is \(\boxed{18}\).
1. **Prime factorization of 72**:
- \( 72 = 2^3 \times 3^2 \)
2. **Prime factorization of 90**:
- \( 90 = 2^1 \times 3^2 \times 5^1 \)
3. **Prime factorization of 54**:
- \( 54 = 2^1 \times 3^3 \)
Next, we identify the common prime factors and select the smallest power of each common factor from all three numbers.
- For the prime factor \(2\):
- The minimum power in the factorizations is \(2^1\) (since \(72\) has \(2^3\), \(90\) has \(2^1\), and \(54\) has \(2^1\)).
- For the prime factor \(3\):
- The minimum power is \(3^2\) (since \(72\) has \(3^2\), \(90\) has \(3^2\), and \(54\) has \(3^3\)).
Now we can find the GCF by multiplying the smallest powers of the common prime factors:
\[
\text{GCF} = 2^1 \times 3^2 = 2 \times 9 = 18
\]
Therefore, the greatest common factor of 72, 90, and 54 is \(\boxed{18}\).
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