The Earth's radius is Re = 6357 km. A location 15,000 km above the surface would be
Re + 15,000 = 21,357 km
from the center.
Since the accleration of gravity, g, is proportional to 1/R^2, where R is the distance from the center of the earth, at that height
g = (6357/21,357)^2 * 9.8 m/s^2
= 0.87 m/s^2
What is the gravity at the height of 15000 km above the earth surface
1 answer