Asked by Bruk
What is the frequency distribution below and determine the range variance and standard deviation of the population function v=1-2-3-4-6-0
F=1-2-3-4-3-2
F=1-2-3-4-3-2
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Answered by
Bot
The frequency distribution shows that the population function has a range of 6, meaning that the values range from 0 to 6.
To find the variance of the population function, we need to find the mean of the values, which is:
(1+2+3+4+6+0)/6 = 2.67
Then we subtract the mean from each value, square the result, and multiply by its frequency:
(1-2.67)^2 * 1 = 2.11
(2-2.67)^2 * 2 = 1.78
(3-2.67)^2 * 3 = 0.30
(4-2.67)^2 * 1 = 1.11
(6-2.67)^2 * 1 = 9.16
(0-2.67)^2 * 2 = 7.12
Adding these values together gives us:
2.11 + 1.78 + 0.30 + 1.11 + 9.16 + 7.12 = 21.58
To find the variance, we divide this sum by the total frequency (10 in this case):
21.58/10 = 2.16
The standard deviation is the square root of the variance, so:
√2.16 = 1.47
Therefore, the range of the population function is 6, the variance is 2.16, and the standard deviation is 1.47.
To find the variance of the population function, we need to find the mean of the values, which is:
(1+2+3+4+6+0)/6 = 2.67
Then we subtract the mean from each value, square the result, and multiply by its frequency:
(1-2.67)^2 * 1 = 2.11
(2-2.67)^2 * 2 = 1.78
(3-2.67)^2 * 3 = 0.30
(4-2.67)^2 * 1 = 1.11
(6-2.67)^2 * 1 = 9.16
(0-2.67)^2 * 2 = 7.12
Adding these values together gives us:
2.11 + 1.78 + 0.30 + 1.11 + 9.16 + 7.12 = 21.58
To find the variance, we divide this sum by the total frequency (10 in this case):
21.58/10 = 2.16
The standard deviation is the square root of the variance, so:
√2.16 = 1.47
Therefore, the range of the population function is 6, the variance is 2.16, and the standard deviation is 1.47.
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