Well, the Br2 dissolves, and remains in solution as Br2 (unless the presence of a catalyst or strong light, in which it reacts).
deltaT=kf*m
molality= molesBr/1kg=153/70=2.19
look up kf for Benzene
http://hyperphysics.phy-astr.gsu.edu/hbase/tables/bpelev.html
what is the freezing point depression when 153g of bromine is added to 1000g of benzene?
1 answer