what is the fraction of 4 weeks is 5 days
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what is the fraction of 4 weeks is 5 days
To find the fraction of 4 weeks that is equal to 5 days, we first need to convert both the weeks and the days to a common unit of time.
There are 7 days in a week, so 4 weeks is equal to 4 x 7 = 28 days.
Now, we can write the fraction:
5 days / 28 days
This fraction cannot be simplified further since 5 and 28 do not have any common factors.
Therefore, the fraction of 4 weeks that is equal to 5 days is 5/28.
There are 7 days in a week, so 4 weeks is equal to 4 x 7 = 28 days.
Now, we can write the fraction:
5 days / 28 days
This fraction cannot be simplified further since 5 and 28 do not have any common factors.
Therefore, the fraction of 4 weeks that is equal to 5 days is 5/28.
Factories 6a+hm+6h+am
I'm sorry, but it seems like the expression you provided is incomplete or contains variables without any context. Can you please provide more information or clarify your statement?
Factories 6a + hm + 6h + am
The expression you provided is:
6a + hm + 6h + am
This is a combination of several terms with variables. It cannot be simplified further unless the values of the variables or any specific relationships between them are given.
6a + hm + 6h + am
This is a combination of several terms with variables. It cannot be simplified further unless the values of the variables or any specific relationships between them are given.
Factories 6a+hm+6h+am
The expression you provided is:
6a + hm + 6h + am
This expression has four terms: 6a, hm, 6h, and am. It cannot be simplified further without more information or specific values for the variables a, h, and m.
6a + hm + 6h + am
This expression has four terms: 6a, hm, 6h, and am. It cannot be simplified further without more information or specific values for the variables a, h, and m.
6a+hm+6h+am
The expression you provided is:
6a + hm + 6h + am
This expression has four terms: 6a, hm, 6h, and am. It cannot be simplified further without more information or specific values for the variables a, h, and m.
6a + hm + 6h + am
This expression has four terms: 6a, hm, 6h, and am. It cannot be simplified further without more information or specific values for the variables a, h, and m.
Expand 6a+hm+6h+am
To expand the expression 6a+hm+6h+am, we can use the distributive property to combine like terms:
= 6a + hm + 6h + am
= (6a + am) + (hm + 6h)
= a(6 + m) + h(m + 6)
So, the expanded form of the expression 6a+hm+6h+am is a(6 + m) + h(m + 6).
= 6a + hm + 6h + am
= (6a + am) + (hm + 6h)
= a(6 + m) + h(m + 6)
So, the expanded form of the expression 6a+hm+6h+am is a(6 + m) + h(m + 6).
Solve the inequality 2-x> 14-3x
To solve the inequality 2 - x > 14 - 3x, we can proceed as follows:
First, let's simplify both sides of the inequality:
2 - x > 14 - 3x
Now, let's collect the x terms on one side of the inequality:
2 + 3x - x > 14 - x - 3x
Simplifying further:
2 + 2x > 14 - 2x
Next, let's isolate the x terms by adding 2x to both sides:
2 + 2x + 2x > 14 - 2x + 2x
Simplifying further:
2 + 4x > 14
Now, let's isolate the constant terms by subtracting 2 from both sides:
2 + 4x - 2 > 14 - 2
Simplifying further:
4x > 12
Finally, let's isolate x by dividing both sides by 4:
4x/4 > 12/4
Simplifying further:
x > 3
So the solution to the inequality 2 - x > 14 - 3x is x > 3.
First, let's simplify both sides of the inequality:
2 - x > 14 - 3x
Now, let's collect the x terms on one side of the inequality:
2 + 3x - x > 14 - x - 3x
Simplifying further:
2 + 2x > 14 - 2x
Next, let's isolate the x terms by adding 2x to both sides:
2 + 2x + 2x > 14 - 2x + 2x
Simplifying further:
2 + 4x > 14
Now, let's isolate the constant terms by subtracting 2 from both sides:
2 + 4x - 2 > 14 - 2
Simplifying further:
4x > 12
Finally, let's isolate x by dividing both sides by 4:
4x/4 > 12/4
Simplifying further:
x > 3
So the solution to the inequality 2 - x > 14 - 3x is x > 3.
What is the area of a rhombus whose diagonals are 12 cm and 8 cm respectively
To find the area of a rhombus, you can use the formula:
Area = (diagonal1 * diagonal2) / 2
In this case, the diagonals are 12 cm and 8 cm respectively. Plugging these values into the formula, we get:
Area = (12 cm * 8 cm) / 2
= 96 cm² / 2
= 48 cm²
Therefore, the area of the rhombus is 48 square centimeters.
Area = (diagonal1 * diagonal2) / 2
In this case, the diagonals are 12 cm and 8 cm respectively. Plugging these values into the formula, we get:
Area = (12 cm * 8 cm) / 2
= 96 cm² / 2
= 48 cm²
Therefore, the area of the rhombus is 48 square centimeters.
Find the amount if simple interest is paid on 443200.00 naira for 5 years at 3.5% per annum
To calculate the simple interest, we can use the formula:
Simple Interest = Principal * Rate * Time
Given that the principal (P) is ₦443200.00, the rate (R) is 3.5% (or 0.035), and the time (T) is 5 years, we can substitute these values into the formula:
Simple Interest = ₦443200.00 * 0.035 * 5
Calculating this expression, we find:
Simple Interest = ₦77,560.00
Therefore, the amount of simple interest paid on ₦443200.00 for 5 years at 3.5% per annum is ₦77,560.00.
Simple Interest = Principal * Rate * Time
Given that the principal (P) is ₦443200.00, the rate (R) is 3.5% (or 0.035), and the time (T) is 5 years, we can substitute these values into the formula:
Simple Interest = ₦443200.00 * 0.035 * 5
Calculating this expression, we find:
Simple Interest = ₦77,560.00
Therefore, the amount of simple interest paid on ₦443200.00 for 5 years at 3.5% per annum is ₦77,560.00.
Evaluate cos 30 degrees+ sin 60 degrees leaving your answer in sure form
To evaluate cos 30 degrees + sin 60 degrees, we can use the values of cosine and sine for these angles:
cos 30 degrees = √3/2
sin 60 degrees = √3/2
Therefore, cos 30 degrees + sin 60 degrees = (√3/2) + (√3/2)
Simplifying further, we have:
cos 30 degrees + sin 60 degrees = (√3 + √3) / 2
Combining like terms, we get:
cos 30 degrees + sin 60 degrees = (2√3) / 2
Dividing both the numerator and denominator by 2, we get:
cos 30 degrees + sin 60 degrees = √3
Therefore, the value of cos 30 degrees + sin 60 degrees, in simplified form, is √3.
cos 30 degrees = √3/2
sin 60 degrees = √3/2
Therefore, cos 30 degrees + sin 60 degrees = (√3/2) + (√3/2)
Simplifying further, we have:
cos 30 degrees + sin 60 degrees = (√3 + √3) / 2
Combining like terms, we get:
cos 30 degrees + sin 60 degrees = (2√3) / 2
Dividing both the numerator and denominator by 2, we get:
cos 30 degrees + sin 60 degrees = √3
Therefore, the value of cos 30 degrees + sin 60 degrees, in simplified form, is √3.
Calculate the interior angle of a regular octagon
To calculate the interior angle of a regular octagon, we can use the formula:
Interior Angle = (180 * (n - 2)) / n
Where n represents the number of sides in the regular polygon.
For an octagon (n = 8), substituting the values into the formula, we get:
Interior Angle = (180 * (8 - 2)) / 8
= (180 * 6) / 8
= 135 degrees
Therefore, the interior angle of a regular octagon is 135 degrees.
Interior Angle = (180 * (n - 2)) / n
Where n represents the number of sides in the regular polygon.
For an octagon (n = 8), substituting the values into the formula, we get:
Interior Angle = (180 * (8 - 2)) / 8
= (180 * 6) / 8
= 135 degrees
Therefore, the interior angle of a regular octagon is 135 degrees.
Find the quadratic equation whose roots are a and -b
To find a quadratic equation with roots a and -b, we can use the fact that the product of the roots of a quadratic equation is equal to the constant term divided by the leading coefficient.
In this case, the roots are a and -b. Therefore, the product of the roots is:
a * (-b) = -ab
To find the quadratic equation, we write it in the form:
x^2 + bx + c = 0
Where b represents the coefficient of x and c represents the constant term.
Since the product of the roots is -ab, we know that c is equal to -ab.
Hence, the quadratic equation with roots a and -b is:
x^2 + (a - b)x - ab = 0
In this case, the roots are a and -b. Therefore, the product of the roots is:
a * (-b) = -ab
To find the quadratic equation, we write it in the form:
x^2 + bx + c = 0
Where b represents the coefficient of x and c represents the constant term.
Since the product of the roots is -ab, we know that c is equal to -ab.
Hence, the quadratic equation with roots a and -b is:
x^2 + (a - b)x - ab = 0
3y^2-5y+2=0
To solve the quadratic equation 3y^2 - 5y + 2 = 0, we can factor it or use the quadratic formula.
Method 1: Factoring
We need to find two numbers whose product is equal to (3 * 2) = 6 and whose sum is equal to (-5).
The numbers that fit these criteria are -3 and -2.
Using these numbers, we can factor the equation as follows:
(3y - 2)(y - 1) = 0
Setting each factor equal to zero, we have:
3y - 2 = 0 --> y = 2/3
y - 1 = 0 --> y = 1
So the solutions to the equation are y = 2/3 and y = 1.
Method 2: Quadratic formula
The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solutions are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our case, a = 3, b = -5, and c = 2.
Using these values in the quadratic formula:
y = (-(-5) ± √((-5)^2 - 4 * 3 * 2)) / (2 * 3)
y = (5 ± √(25 - 24)) / 6
y = (5 ± √1) / 6
y = (5 ± 1) / 6
So the solutions are y = 6/6 = 1 and y = 4/6 = 2/3.
Therefore, the solutions to the equation 3y^2 - 5y + 2 = 0 are y = 2/3 and y = 1.
Method 1: Factoring
We need to find two numbers whose product is equal to (3 * 2) = 6 and whose sum is equal to (-5).
The numbers that fit these criteria are -3 and -2.
Using these numbers, we can factor the equation as follows:
(3y - 2)(y - 1) = 0
Setting each factor equal to zero, we have:
3y - 2 = 0 --> y = 2/3
y - 1 = 0 --> y = 1
So the solutions to the equation are y = 2/3 and y = 1.
Method 2: Quadratic formula
The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solutions are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our case, a = 3, b = -5, and c = 2.
Using these values in the quadratic formula:
y = (-(-5) ± √((-5)^2 - 4 * 3 * 2)) / (2 * 3)
y = (5 ± √(25 - 24)) / 6
y = (5 ± √1) / 6
y = (5 ± 1) / 6
So the solutions are y = 6/6 = 1 and y = 4/6 = 2/3.
Therefore, the solutions to the equation 3y^2 - 5y + 2 = 0 are y = 2/3 and y = 1.
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