What is the formula for the nth term for the following sequence: 40, 16, 6.4, 2.56, 1.024, 0.4096?

Answer 1

recall that

4^1=4
4^2=16
4^3=64

But, each term is multiplied by 10,1,.1,... = 10^(2-n)

so, Tn = 4^n * 10^(2-n) = 100 (4/10)^n

Answer 2

40 / (2.5 ^ n-1)

Answer 3

Yeah

Answer 4

Shredder is correct .steve is not correct

Answer 5

Ahem.

40/(2.5^n-1)
= 40*2.5/2.5^n
= 100/2.5^n
= 100 / (10/4)^n
= 100 * (4/10)^n

Answer 6

Steve dat nt it . Try this one . .a/2.5^n -1.0 . To check maybe it goes along wit d ques. And is this ogonna