The force on the elevator can be calculated using Newton's second law of motion, which states that force is equal to mass times acceleration.
In this case, the mass of the elevator is 1000 kg and the acceleration due to gravity is 9.8 m/s^2. Therefore, the force on the elevator is:
Force = mass * acceleration
Force = 1000 kg * 9.8 m/s^2
Force = 9800 N
Therefore, the force on the 1000 kg elevator that is falling freely at 9.8 m/s^2 is 9800 Newtons.
What is the force on a 1000 kg elevator that is falling freely at 9.8 m/sec/sec?
1 answer