What is the first 12 term of an ap whose first term is 15 and the common difference is 13

Answer 1

In an Arithmetic progression:

a(n+1) = an + d

where

a1 = first term

d = the common difference

a1 = a1 = 15

a2 = a1 + d = 15 + 13 = 28

a3 = a2 + d = 28 + 13 = 41

a4 = a3 + d = 41 + 13 = 54

etc.

Answer 2

an = the nth term

a(n+1) = the n+1 th term