In an Arithmetic progression:
a(n+1) = an + d
where
a1 = first term
d = the common difference
a1 = a1 = 15
a2 = a1 + d = 15 + 13 = 28
a3 = a2 + d = 28 + 13 = 41
a4 = a3 + d = 41 + 13 = 54
etc.
What is the first 12 term of an ap whose first term is 15 and the common difference is 13
2 answers
an = the nth term
a(n+1) = the n+1 th term
a(n+1) = the n+1 th term