call specific heat of gold G
call specific heat of water W
(I am not about to get a book out)
3 (G) (99-T) = .22 (W)(T-25)
T will be pretty close to boiling.
what is the final temperature when a 3.0 kg gold bar at 99 degrees Celsius is dropped into 0.22 kg of water at 25 degrees Celsius?
3 answers
TF=47
42