What is the final temperature when 8.0 x 105 J are added to 1.50 kg of ice at 0.0 °C?

Answer 1

heat=mass*Lf+mass*specificheat*(tf-0)

8E5=1.5kg* 334kJ/kg + 1.5kg*4.18kJ/kg-C;* Tf

solve for Tf