What is the final temperature (degrees celcius) of 1.36g of water with an initial temperature of 23.0degrees celcius after 6.420J of heat is added to it?

Answer 1

m=dv
mol C2H2=m/molar mass
heat(q)= (delta H)(mol)

Answer 2

q = [mass H2O x specific heat H2O x (Tfinal-Tinitial) = 0