Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. T...Asked by Danny
What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N.
The steel hanger in question has a cross sectional area of 7.600cm^2
ANS= Round to 3 decimal places
Safety factor = design load/ load
= 550.000MPa = 550000000Pa
= 550000000/ 64000
= 8593.75
tension design = 550MPa * 0.076M^2
= 18.000
Have I messed thing up? Please let me know if I am on the right track. Thanks.
The steel hanger in question has a cross sectional area of 7.600cm^2
ANS= Round to 3 decimal places
Safety factor = design load/ load
= 550.000MPa = 550000000Pa
= 550000000/ 64000
= 8593.75
tension design = 550MPa * 0.076M^2
= 18.000
Have I messed thing up? Please let me know if I am on the right track. Thanks.
Answers
Answered by
Damon
550*10^6 Pa ultimate = 5.50*10^8 Pa
7.6 cm^2 /100/100 = 7.6*10^-4 m^2
(You only divided by 100 but it is squared so 10,000 cm^2/m^2
6.4 * 10^4 N/7.6*10^-4 m^2 = .842 *10^8 N/m^2 or Pascals real load
5.50*10^8/ .842*10^8 = 6.53
7.6 cm^2 /100/100 = 7.6*10^-4 m^2
(You only divided by 100 but it is squared so 10,000 cm^2/m^2
6.4 * 10^4 N/7.6*10^-4 m^2 = .842 *10^8 N/m^2 or Pascals real load
5.50*10^8/ .842*10^8 = 6.53
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.