What is the expression (2k+1)(k-4) and (-2y+5)(y+3) simplified?

Answer 1

To simplify (2k+1)(k-4), we can use the distributive property:

(2k+1)(k-4) = 2k(k-4) + 1(k-4)

Now we can simplify each term separately:

2k(k-4) = 2k^2 - 8k

1(k-4) = k - 4

Putting the terms back together, we get:

(2k+1)(k-4) = 2k^2 - 8k + k - 4

Simplifying further:

(2k+1)(k-4) = 2k^2 - 7k - 4

To simplify (-2y+5)(y+3), we can again use the distributive property:

(-2y+5)(y+3) = -2y(y+3) + 5(y+3)

Simplifying each term separately:

-2y(y+3) = -2y^2 - 6y

5(y+3) = 5y + 15

Putting the terms back together:

(-2y+5)(y+3) = -2y^2 - 6y + 5y + 15

Simplifying further:

(-2y+5)(y+3) = -2y^2 - y + 15