The van't Hoff factor (i) represents the number of particles a solute dissociates into when dissolved in a solvent. For NaC2H3O2, also known as sodium acetate, it will dissociate into two ions in an aqueous solution:
NaC2H3O2 (aq) → Na+ (aq) + C2H3O2- (aq)
Since there are two ions produced from one solute particle, the expected van't Hoff factor for NaC2H3O2 in an aqueous solution, assuming 100% dissociation, is i = 2.
What is the expected van't Hoff factor for NaC2H3O2 in an aqueous solution, assuming 100% dissociation.
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