What is the equilibrium constant kc for the reaction if 7 mol of ammonia in 14 L flask.at equilibrium 0.2 M ammonium was found in the flask

Answer 1

The equilibrium constant (Kc) for the reaction involving ammonia (NH3) is given by:

NH3 ⇌ NH4+

The equation for the reaction is:

NH3 ⇌ NH4+

Since the concentration of ammonia at equilibrium is 0.2 M, we can write the expression for Kc as follows:

Kc = [NH4+]/[NH3] = 0.2/7 = 0.0286

Therefore, the equilibrium constant (Kc) for the reaction involving ammonia is 0.0286.