To find the equation of a line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we need to find the values of m and b.
Given the points (-1,5) and (1,-1), we can calculate the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Using the coordinates of the two points, we find:
m = (-1 - 5) / (1 - (-1))
m = -6 / 2
m = -3
Now that we have the slope (m), we can use one of the given points to find the y-intercept (b). Let's use the point (-1,5):
y = mx + b
5 = -3(-1) + b
5 = 3 + b
b = 5 - 3
b = 2
Therefore, the equation of the line in slope-intercept form is:
y = -3x + 2
What is the equation of this line in slope-intercept form?
(-1,5) (1,-1)
Responses
y=3x−2
y equals 3 x minus 2
y = 3x + 2
y, = 3, x, + 2
y=−3x+2
y equals negative 3 x plus 2
y=−13x+2
1 answer
1 answer