What is the equation of the line that passes through the points (−3,4) and (−6,3)? Write the answer in slope-intercept form.

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1 answer

To find the equation of the line that passes through the points \((-3, 4)\) and \((-6, 3)\), we first need to calculate the slope of the line using the formula:

\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

Let \((x_1, y_1) = (-3, 4)\) and \((x_2, y_2) = (-6, 3)\). Plugging in these values:

\[ m = \frac{3 - 4}{-6 - (-3)} = \frac{-1}{-6 + 3} = \frac{-1}{-3} = \frac{1}{3} \]

Now we have the slope \(m = \frac{1}{3}\).

Next, we can use the point-slope form of the equation of a line, which is given by:

\[ y - y_1 = m(x - x_1) \]

Using one of the points, say \((-3, 4)\), we can substitute in the values:

\[ y - 4 = \frac{1}{3}(x + 3) \]

Now we will simplify this equation:

\[ y - 4 = \frac{1}{3}x + 1 \]

Adding 4 to both sides:

\[ y = \frac{1}{3}x + 1 + 4 \] \[ y = \frac{1}{3}x + 5 \]

Thus, in slope-intercept form \(y = mx + b\), the equation of the line is:

\[ y = \frac{1}{3}x + 5 \]

So, your answer is:

\[ y = \frac{1}{3}x + 5 \]