To find the equation of the line in slope-intercept form (y = mx + b), we need to find the slope (m) and the y-intercept (b).
First, let's find the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Using the given points (-3, 4) and (-6, 3), we have:
m = (3 - 4) / (-6 - (-3))
m = -1 / (-6 + 3)
m = -1 / (-3)
m = 1/3
Now, let's find the y-intercept (b) using the formula:
b = y - mx
Using the point (-3, 4):
b = 4 - (1/3)(-3)
b = 4 + 1
b = 5
Therefore, the equation of the line that passes through the points (-3, 4) and (-6, 3) is:
y = (1/3)x + 5
What is the equation of the line that passes through the points (−3,4) and (−6,3) ? Write the answer in slope-intercept form.(1 point)
y=(
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1 answer