What is the equation of the line that passes through the points (−3,4) and (−6,3) ? Write the answer in slope-intercept form.(1 point)%0D%0Ay=()x+

Answer 1

To find the equation of a line using the slope-intercept form (y = mx + b), we need to find the slope (m) and the y-intercept (b).

The slope (m) is given by the formula m = (y₂ - y₁) / (x₂ - x₁), where (x₁, y₁) and (x₂, y₂) are the coordinates of the given points.

Given points: (−3, 4) and (−6, 3)
x₁ = -3, y₁ = 4
x₂ = -6, y₂ = 3

m = (3 - 4) / (-6 - (-3))
m = -1 / (-3)
m = 1/3

Now we can substitute the slope (m) and one of the given points (−3, 4) into the slope-intercept form to find the y-intercept (b):

4 = (1/3)(-3) + b
4 = -1 + b
b = 4 + 1
b = 5

Therefore, the equation of the line in slope-intercept form is:
y = (1/3)x + 5