What is the equation of the line that passes through the points (−3,4) and (−6,3) ? Write the answer in slope-intercept form.(1 point)

Answer 1

To find the equation of the line that passes through the points (-3,4) and (-6,3), we first need to find the slope of the line.

The slope (m) of a line passing through two points (x1, y1) and (x2, y2) can be found using the formula:

m = (y2 - y1)/(x2 - x1)

Using the points (-3,4) and (-6,3), we have:

m = (3 - 4)/(-6 - (-3))
= -1/-3
= 1/3

Now that we have the slope, we can plug it into the slope-intercept form of a line, which is y = mx + b. Using the point (-3,4) along with the slope, we can solve for b:

4 = (1/3)(-3) + b
4 = -1 + b
b = 5

Now, we have the slope (m) and the y-intercept (b), so we can write the equation of the line in slope-intercept form:

y = (1/3)x + 5