To find the equation of the line passing through two points, we can use the slope-intercept form of a linear equation which is given by: y = mx + b, where m is the slope and b is the y-intercept.
First, let's find the slope (m) using the formula: m = (y2 - y1)/(x2 - x1)
Given the points (-3,4) and (-6,3), we have:
x1 = -3, y1 = 4
x2 = -6, y2 = 3
m = (3 - 4)/(-6 - (-3))
= -1/(-6 + 3)
= -1/-3
= 1/3
So the slope (m) is 1/3.
Now, we can use the point-slope form of a linear equation to find the y-intercept (b).
Using the point (-3,4), we substitute x = -3 and y = 4 into the equation y = mx + b to get: 4 = (1/3)(-3) + b
Simplifying and solving for b:
4 = -1 + b
b = 4 + 1
b = 5
So the y-intercept (b) is 5.
Now we can write the equation of the line in slope-intercept form: y = mx + b
Substituting the values m = 1/3 and b = 5, the equation becomes:
y = (1/3)x + 5
Thus, the equation of the line passing through the points (-3,4) and (-6,3) in slope-intercept form is: y = (1/3)x + 5.
What is the equation of the line that passes through the points (−3,4) and (−6,3) ? Write the answer in slope-intercept form.(1 point) y=()x+
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