To find the equation of a line, we use the point-slope form, which is:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line and m is the slope.
Given that the point is (6, -8) and the slope is -2/3, we can substitute these values into the equation:
y - (-8) = (-2/3)(x - 6)
Simplifying:
y + 8 = (-2/3)(x - 6)
Multiplying (-2/3) by (x - 6) gives:
y + 8 = (-2/3)x + 4
Subtracting 8 from both sides:
y = (-2/3)x - 4 - 8
Simplifying:
y = (-2/3)x - 12
So, the equation of the line that passes through the point (6, -8) with a slope of -2/3 is y = (-2/3)x - 12.
What is the equation of the line that passes through the point left bracket, 6, comma, minus, 8, right bracket(6,−8) and has a slope of minus, start fraction, 2, divided by, 3, end fraction−
3
2
?
3 answers
try again
Apologies for the confusion. Let's solve it again.
We are given that the line passes through the point (6, -8) and has a slope of -3/2.
Using the point-slope formula, the equation of the line is:
y - y1 = m(x - x1)
Substituting the values, we have:
y - (-8) = (-3/2)(x - 6)
Simplifying:
y + 8 = (-3/2)(x - 6)
Multiplying (-3/2) by (x - 6) gives:
y + 8 = (-3/2)x + 9
Subtracting 8 from both sides:
y = (-3/2)x + 1
So, the equation of the line that passes through the point (6, -8) with a slope of -3/2 is y = (-3/2)x + 1.
We are given that the line passes through the point (6, -8) and has a slope of -3/2.
Using the point-slope formula, the equation of the line is:
y - y1 = m(x - x1)
Substituting the values, we have:
y - (-8) = (-3/2)(x - 6)
Simplifying:
y + 8 = (-3/2)(x - 6)
Multiplying (-3/2) by (x - 6) gives:
y + 8 = (-3/2)x + 9
Subtracting 8 from both sides:
y = (-3/2)x + 1
So, the equation of the line that passes through the point (6, -8) with a slope of -3/2 is y = (-3/2)x + 1.