What is the equation of the line that passes through the point (8,3) and has a slope of -1/4?

Answer 1

The equation of a line can be written in slope-intercept form, which is:

y = mx + b

where m is the slope and b is the y-intercept.

Given that the slope (m) is -1/4 and the point (8,3) is on the line, we can use the point-slope formula:

y - y1 = m(x - x1)

where (x1,y1) is the point (8,3).

Plugging in the values, we have:

y - 3 = (-1/4)(x - 8)

Simplifying, we get:

y - 3 = (-1/4)x + 2

Adding 3 to both sides, we have:

y = (-1/4)x + 2 + 3

y = (-1/4)x + 5

So, the equation of the line that passes through the point (8,3) and has a slope of -1/4 is y = (-1/4)x + 5.