What is the equation of the line that goes through the points (4,3) and (8,2) ?

Answer 1

To find the equation of the line that goes through (4,3) and (8,2), we can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

where (x1, y1) is one of the given points and m is the slope of the line. We can find the slope using the slope formula:

m = (y2 - y1)/(x2 - x1)

where (x1, y1) and (x2, y2) are the two given points. Substituting the values, we get:

m = (2 - 3)/(8 - 4) = -1/4

Now we can choose either of the given points and substitute into the point-slope form. Let's use (4,3):

y - 3 = (-1/4)(x - 4)

Expanding and simplifying, we get:

y = (-1/4)x + 7/2

This is the equation in slope-intercept form, where the slope is -1/4 and the y-intercept is 7/2.