What is the equation of the circle written in the form left-parenthesis x minus h right-parenthesis squared plus left-parenthesis y minus k right-parenthesis squared equals r squared? Enter the values of h, k, and r in the boxes.

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The equation of a circle written in the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle and r is the radius.

h = ___
k = ___
r = ___
what is the value for H, K, R
I need more information to determine the values of h, k, and r. Please provide the specific equation of the circle in the form (x - h)^2 + (y - k)^2 = r^2.
the circle is 8 units in diameter and sits on the coordinate (2, 0) and crosses the y axis by to unit to the left
To find the values of h, k, and r, we can use the information given:

1. The circle has a diameter of 8 units, so the radius is half of the diameter, which is 8 / 2 = 4 units.
2. The center of the circle is at the point (h, k) = (2, 0).
3. The circle crosses the y-axis 2 units to the left, which means the circle also crosses the y-axis at (2, 2) and (2, -2).

Therefore:
- h = 2
- k = 0
- r = 4

The equation of the circle in the form (x - h)^2 + (y - k)^2 = r^2 would be:
(x - 2)^2 + y^2 = 16
the center of the circle is (2, 4)
Thank you for the correction. If the center of the circle is (2,4) and the radius is 4, then:

h = 2, k = 4, r = 4

The equation of the circle in the form (x - h)^2 + (y - k)^2 = r^2 is:
(x - 2)^2 + (y - 4)^2 = 16
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