What is the equation of a circle with its center at (0,3) and a diameter of 6.

Answers:
a. x^2+(y+3)^2=9
b. x^2-(y-3)^2=9
c. x^2+y^2-6y=0
d. x^2+(y_3)^2=0
e. x^2+(y-3)^2=36

3 answers

If we know that the equation of a circle with the centre at (x0,y0) and radius r:
(x-x0)² + (y-y0)² = r²
Which choice would you take?

I think it's b.

b. is correct!