What is the equation for the axis of symmetry on the parabola created by y=3(x−1)^2−12

Question

?(1 point)

Answer 1

The equation for the axis of symmetry of a parabola given in vertex form \( y = a(x - h)^2 + k \) is \( x = h \), where \( (h, k) \) is the vertex of the parabola.

For the equation you provided:

\[ y = 3(x - 1)^2 - 12 \]

Here, \( h = 1 \) and \( k = -12 \). Hence, the axis of symmetry is:

\[ x = 1 \]

So, the equation for the axis of symmetry is \( x = 1 \).