What is the energy of a photon with a frequency of 2.2 × 1016 Hz? Planck’s constant is 6.63 × 10–34 J•s.

1.5 × 10–17 J
8.8 × 10–17 J
1.5 × 10–16 J
8.8 × 10–16 J

1 answer

To calculate the energy of a photon, you can use the formula:

\[ E = h \cdot f \]

where:

  • \( E \) is the energy of the photon,
  • \( h \) is Planck's constant (\( 6.63 \times 10^{-34} , \text{J·s} \)),
  • \( f \) is the frequency of the photon (\( 2.2 \times 10^{16} , \text{Hz} \)).

Now, substituting the values into the formula:

\[ E = (6.63 \times 10^{-34} , \text{J·s}) \cdot (2.2 \times 10^{16} , \text{Hz}) \]

\[ E = 1.459 \times 10^{-17} , \text{J} \]

Now, rounding to two significant figures (as in the frequency), we get:

\[ E \approx 1.5 \times 10^{-17} , \text{J} \]

Therefore, the energy of the photon is approximately:

1.5 × 10–17 J.