The end behavior of the exponential function f(x) = 3/2 * (4/5)^x is as follows:
As x approaches positive infinity (∞), f(x) approaches 0. This means that the function decreases and gets arbitrarily close to 0, but it never actually reaches 0.
As x approaches negative infinity (-∞), f(x) approaches infinity (∞). This implies that the function increases without bound as x becomes more negative.
What is the end behavior of the exponential function
f(x) = 3/2 × {4/5}^x ?
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