What is the empirical formula for a molecule containing 52.20 grams manganese (Mn0 and 3.80 grams of Carbon (c)?

Answer 1

mols Mn = grams/atomic mass
mols C = grams/atomic mass

Now find the ratio to each other with the smallest being 1.00. The easy way to do that is to divide the smaller number by itself (which makes it 1.00), the divide the other number by the same small number. Round to whole numbers.
Post your work if you get stuck.

Answer 2

Mn3C