What is the electric field between two parallel plates if the electric potential difference between the plates is 24 V and the plates are 65 mm apart?

Question

0.0027 N/C
1.6 N/C
369 N/C
1560 N/C

Answer 1

To calculate the electric field \( E \) between two parallel plates, you can use the formula:

\[ E = \frac{V}{d} \]

where

• \( E \) is the electric field,
• \( V \) is the electric potential difference (in volts),
• \( d \) is the distance between the plates (in meters).

Given:

• \( V = 24 , \text{V} \)
• \( d = 65 , \text{mm} = 0.065 , \text{m} \) (since 1 mm = 0.001 m)

Now substituting the values into the formula:

\[ E = \frac{24 , \text{V}}{0.065 , \text{m}} \approx 369.23 , \text{N/C} \]

Rounding this to significant figures, we get:

\[ E \approx 369 , \text{N/C} \]

Thus, the electric field between the plates is approximately 369 N/C.