The efficiency of a light bulb is calculated by dividing the useful output energy (light energy) by the input energy and then multiplying by 100%.
In this case, the light bulb produces 30 J of light energy and requires an input of 120 J of electrical energy.
Efficiency = (Output energy / Input energy) * 100%
Efficiency = (30 J / 120 J) * 100%
Efficiency = 0.25 * 100%
Efficiency = 25%
Therefore, the efficiency of the light bulb is 25%.
What is the efficiency of a light bulb if it produces 30 J of light energy, with an input of 120 J of electrical energy?(1 point) Responses 25% 25% 15% 15% 90% 90% 40%
1 answer