In parallel connection, the effective capacitance (Cp) is equal to the sum of the individual capacitances:
Cp = 2µF + 6µF = 8µF
In series connection, the effective capacitance (Cs) is given by the reciprocal of the sum of the reciprocals of the individual capacitances:
Cs = 1 / (1/2µF + 1/8µF) = 1 / (4/8µF + 1/8µF) = 1 / (5/8µF) = 8µF / 5 = 1.6µF
Therefore, the effective capacitance of the three capacitances is 1.6µF.
What is the effective capacitance of Three capacitance in which 2ñF and 6ñF connected in parallel then 2ñF is connected in series.
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