Asked by Amelia
What is the domain of f (x) = sqr root of x^2 - 5x - 14?
Answers
Answered by
drwls
You need to use parentheses to clarify what number you are taking the square root of. I assume it is
x^2 - 5x - 14.
It would have to be a positive number or zero. That will help you establish the domain.
x^2 -5x -14 is zero when (x-7)(x+2) = 0, which means at x = -2 and x = 7.
Between x=-2 and +7, it is negative.
The domain is therefore x<-2 and x>+5
x^2 - 5x - 14.
It would have to be a positive number or zero. That will help you establish the domain.
x^2 -5x -14 is zero when (x-7)(x+2) = 0, which means at x = -2 and x = 7.
Between x=-2 and +7, it is negative.
The domain is therefore x<-2 and x>+5
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