What is the distance from the point (-1, -3) to the line y = 2?
How do i do this?
2 answers
In ABC, what is the angle opposite ? I also need help with this one.
In general, the distance of the point
P0 : (x0,y0)
from the line
L : ax+by+c = 0
is given by:
Distance = |ax0+by0+c|/sqrt(a²+b²) ...(1)
where the pair of | | in the numerator represents the absolute value.
In the given case,
P0 : (-1,-3)
or x0=-1, y0=-3
and
L : y - 2 = 0
or a=0, b=1, c=-2
Substitute these values in (1) to get the distance required.
P0 : (x0,y0)
from the line
L : ax+by+c = 0
is given by:
Distance = |ax0+by0+c|/sqrt(a²+b²) ...(1)
where the pair of | | in the numerator represents the absolute value.
In the given case,
P0 : (-1,-3)
or x0=-1, y0=-3
and
L : y - 2 = 0
or a=0, b=1, c=-2
Substitute these values in (1) to get the distance required.