The distance between the points (-4, 3) and (6, -1) can be calculated using the distance formula:
√((6 - (-4))^2 + (-1 - 3)^2)
= √((6 + 4)^2 + (-1 - 3)^2)
= √(10^2 + (-4)^2)
= √(100 + 16)
= √116
Therefore, the distance between the points (-4, 3) and (6, -1) is √116.
What is the distance between the points (-4, 3) and (6, -1)? Leave your answer in exact form.
(1 point)
Responses
104−−−√
square root of 104
108−−−√
square root of 108
116−−−√
square root of 116
84−−√
3 answers
I thought it was 4√21.
Let's reassess the calculation for the distance between the points (-4, 3) and (6, -1):
√((6 - (-4))^2 + (-1 - 3)^2)
= √((6 + 4)^2 + (-1 - 3)^2)
= √(10^2 + (-4)^2)
= √(100 + 16)
= √116
Therefore, the distance between the points (-4, 3) and (6, -1) is indeed √116, which is equal to 4√29 or approximately 10.77. Thank you for pointing out the incorrect simplification.
√((6 - (-4))^2 + (-1 - 3)^2)
= √((6 + 4)^2 + (-1 - 3)^2)
= √(10^2 + (-4)^2)
= √(100 + 16)
= √116
Therefore, the distance between the points (-4, 3) and (6, -1) is indeed √116, which is equal to 4√29 or approximately 10.77. Thank you for pointing out the incorrect simplification.
1 answer