what is the distance between the points (-1,7) and (5,7)?
3 answers
why isnt anyone answering my question
The distance is the hypotenuse of a right triangle where one leg is the x distance and the other leg is the y distance. In this case, the y values are the same so the distance between the points is simply the x distance.
distance between any two points (a,b) and (c,d)
= √[(a-c)^2 + (b-d)^2]
so for yours
distance = √(6^2 + 0^2)
= √36 = 6
since for your points have the same y value, thus have the same height, they lie in a horizontal line.
Therefore we could have just taken the horizontal distance from -1 to 5, which of course is 6
= √[(a-c)^2 + (b-d)^2]
so for yours
distance = √(6^2 + 0^2)
= √36 = 6
since for your points have the same y value, thus have the same height, they lie in a horizontal line.
Therefore we could have just taken the horizontal distance from -1 to 5, which of course is 6