What is the distance between ( 19,-6) and (8, -6) in a coordinate plane ?

Answer 1

The distance between (19,-6) and (8, -6) can be calculated using the distance formula:

d = √((x2 - x1)^2 + (y2 - y1)^2)

where (x1, y1) = (19, -6) and (x2, y2) = (8, -6)

d = √((8 - 19)^2 + (-6 - (-6))^2)
d = √((-11)^2 + 0)
d = √(121 + 0)
d = √121
d = 11

Therefore, the distance between (19,-6) and (8, -6) is 11 units.