What is the difference of the polynomials?

(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

1 answer

To find the difference of the polynomials, we need to distribute the negative sign in front of the second polynomial:

(–2x^3y^2 + 4x^2y^3 – 3xy^4) - (6x^4y - 5x^2y^3 - y^5)
= -2x^3y^2 + 4x^2y^3 - 3xy^4 - 6x^4y + 5x^2y^3 + y^5

Combine like terms:

= -6x^4y - 2x^3y^2 + 9x^2y^3 - 3xy^4 + y^5

Therefore, the difference of the polynomials is -6x^4y - 2x^3y^2 + 9x^2y^3 - 3xy^4 + y^5.