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what is the derivative of y=�ã(3x)
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assuming that means √(3x), use the chain rule
d/dx u^n = n*u^(n-1) * du/dx where u=3x and n = 1/2:
y = (3x)^(1/2)
y' = 1/2 * (3x)^(-1/2) * 3
= 3/(2√(3x))
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