Exponential rule:
d(a^x)/dx = ln(a) a^x
For logarithms to arbitrary base:
d(loga(x))/dx
=d(ln(x)/ln(a))/dx
=ln(a)/x
Finally, the product rule:
d(uv)/dx = u dv/dx + v du/dx
set
u=5^x,
v=log6(x)
=ln(x)/ln(6)
Can you take it from here?
What is the derivative of f(x)=5^x log6(x)?
2 answers
For logarithms to arbitrary base:
d(loga(x))/dx
=d(ln(x)/ln(a))/dx
=1/(ln(a)*x)
d(loga(x))/dx
=d(ln(x)/ln(a))/dx
=1/(ln(a)*x)