Question

What is the density of a piece of wood that has a mass of 7 g in a volume of 10 centimeters 3 1 cm 3 equals 1 mL so 10 cm 3 equal 10 mL what is the density of the wood when the piece of wood is cut in half A 0.7 g / centimeter 3 and 0.35 g centimeter 3 B 0.7 g / centimeter 3 and still 0.7 g / centimeter 3 C 0.7 g / centimeter 3 and 1.4 g / centimeters 3 D 70 g / centimeters 3 and still 70 g / centimeter 3

Answer 1

To calculate the density of the piece of wood, we use the formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

Given that the mass of the piece of wood is 7 g and the volume is 10 cm³, we can find the density:

\[ \text{Density} = \frac{7 , \text{g}}{10 , \text{cm}^3} = 0.7 , \text{g/cm}^3 \]

Now, if the piece of wood is cut in half, each half will have:

• Mass: \( \frac{7 , \text{g}}{2} = 3.5 , \text{g} \)
• Volume: \( \frac{10 , \text{cm}^3}{2} = 5 , \text{cm}^3 \)

Now, we can find the density of each half:

\[ \text{Density} = \frac{3.5 , \text{g}}{5 , \text{cm}^3} = 0.7 , \text{g/cm}^3 \]

Therefore, the density of the wood remains the same after cutting it in half, which is still \(0.7 , \text{g/cm}^3\).

So the correct answer is B: 0.7 g/cm³ and still 0.7 g/cm³.