What is the density of a 700 kg object with a volume of 649 m3? (Density: D = D = m over v.)

Question

0.927 kg/m3
.4543 kg/m3
1.079 kg/m3
4.543 kg/m3

Answer 1

To find the density \( D \) of the object, you can use the formula:

\[ D = \frac{m}{v} \]

Where:

• \( m \) is the mass,
• \( v \) is the volume.

Given:

• \( m = 700 , \text{kg} \)
• \( v = 649 , \text{m}^3 \)

Substituting the values into the formula:

\[ D = \frac{700 , \text{kg}}{649 , \text{m}^3} \]

Calculating this gives:

\[ D \approx 1.07898 , \text{kg/m}^3 \]

Rounding to three decimal places, the density is approximately:

\[ D \approx 1.079 , \text{kg/m}^3 \]

Thus, the correct answer is:

1.079 kg/m³.