What is the date today if July 7 was six days before one day after 4 days before the day before the day before 8 days after the day before yesterday

1 answer

Let's break down the statement step by step to determine the date.

  1. "the day before yesterday": Let's call today \( T \). The day before yesterday would be \( T - 2 \).

  2. "8 days after the day before yesterday": This would be \( (T - 2) + 8 = T + 6 \).

  3. "the day before" that: This means we go one day back from \( T + 6 \), which is \( (T + 6) - 1 = T + 5 \).

  4. "4 days before" that: Now we subtract 4 days from \( T + 5 \), which yields \( (T + 5) - 4 = T + 1 \).

  5. "one day after" that: Next, we add one day, resulting in \( (T + 1) + 1 = T + 2 \).

  6. "six days before" that: Finally, we subtract 6 days from \( T + 2 \), giving us \( (T + 2) - 6 = T - 4 \).

So the original statement boils down to saying that July 7 was \( T - 4 \). This means:

\[ T - 4 = \text{July 7} \]

To find \( T \), we can express this as:

\[ T = \text{July 7} + 4 \text{ days} \]

Calculating \( T \):

  • July 8 (1 day after July 7)
  • July 9 (2 days after July 7)
  • July 10 (3 days after July 7)
  • July 11 (4 days after July 7)

Thus, today is July 11.