The balanced symbol equation for the reaction between copper(II) oxide and sulfuric acid to produce copper(II) sulfate and water can be written as follows:
\[ \text{CuO} + \text{H}_2\text{SO}_4 \rightarrow \text{CuSO}_4 + \text{H}_2\text{O} \]
In this reaction:
- CuO is copper(II) oxide,
- H₂SO₄ is sulfuric acid,
- CuSO₄ is copper(II) sulfate, and
- H₂O is water.
This equation is balanced as each side contains one copper atom, one sulfur atom, four oxygen atoms, and two hydrogen atoms.