Question

What is the correct simplification of 24335
?(1 point)
Responses

3
3

9
9

27
27

81

Answer 1

To simplify \( 24335 \), let's first check if it's divisible by the numbers given in your options: 3, 9, 27, and 81.

1. **Divisibility by 3:** A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits in \( 24335 \) is \( 2 + 4 + 3 + 3 + 5 = 17 \). Since 17 is not divisible by 3, \( 24335 \) is not divisible by 3.

2. **Divisibility by 9:** For a number to be divisible by 9, the sum of its digits must be divisible by 9. Since 17 is also not divisible by 9, \( 24335 \) is not divisible by 9.

3. **Divisibility by 27:** To check for divisibility by 27, we can see if \( 24335 \) divided by 27 yields an integer. Performing the division:
\[
24335 \div 27 \approx 902.037 \quad \text{(not an integer)}
\]
Thus, \( 24335 \) is not divisible by 27.

4. **Divisibility by 81:** Similarly, we check for 81:
\[
24335 \div 81 \approx 300.43 \quad \text{(not an integer)}
\]
Hence, \( 24335 \) is not divisible by 81.

Since \( 24335 \) is not divisible by any of the choices given (3, 9, 27, 81), none of these simplifications are correct.

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