What is the concentration of the resulting solution when 250 mL of 0.1 M K3PO4 and 300 ml of 0.5 M K3PO4 are mixed?

Answer 1

n1 = cv = 0.1x0.25 = 0.025mol

n2 = cv = 0.5x0.3 = 0.15mol

so the total mole after mixing is;

0.025+0.15 = 0.175mole

and the total volume is;
250+300 = 550mL = 0.55L

thus the concentration is;

total mole/total volume = 0.175mol/0.55L = 0.32mol/L

hope that helps...

Answer 2

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